Kind of a newbie questions, but I would like to know what the consensus is.
Thanks,
Thomas Gainer
Kind of a newbie questions, but I would like to know what the consensus is.
Thanks,
Thomas Gainer
Hmm, until it breaks the application?
Latency is what matters.
That is unless your TTL expires prematurely; in this case
defined as before the applications endpoints can reach each
other (which in turn could theoretically be a function of
latency as well).
I think that we can safely say that the answer is 255.
- Daniel Golding
Douglas Adams, had he done routing, would say 42. Sadly he's
no longer with us.
You won't get a concensus or a summary, but if I post
you're sure to get many opinions with people correcting
or disagreeing, or ranting about nonsequiter things
in a pedantic way, so I'll try to help, or at least incite
a flurry of vindicative responses.
I believe the answer is A/ It Depends, and B/ Usually 6 to 8
routed hops for each AS.
In general, a network operator must be considerate of the
lowest-common-denominator traffic on one's network.
With regards to hop-count, many would say that Windows 95 (98?)
is the LCD, as it emits IP packets (by default) with a TTL
of 32 (Thirty-Two). I believe Win2k (maybe 98) has a default
TTL of 128. I assume that WinME and WinXP are at 128 or more
as well.
It is fairly reasonable to consider that most (90+%) traffic
goes through at most 4 ASes:
(no AS) Client ->
AS 1. Upstream AS of "client"
AS 2. "Tier 1" Upstream to #1
AS 3. "Tier 1" Peer and Upstream to #4
AS 4. Upstream AS of "server"
-> Server (no AS)
Since there are 4 ASes, and 32 hops, each AS should get
something close to 8 hops. Add a few at each end for
aggregation, and you can get give each AS 6 hops, with
some leftover for end-network traffic.
MIN_HOPS_PER_AS = ( LCD_TTL - (END_TTL * 2) ) / MAX_REG_AS_HOPS)
or, MIN_HOPS_PER_AS = ( ( 32 - (2 * 2)) / 4 )
MIN_HOPS_PER_AS = ( ( 32 - 4) / 4 )
MIN_HOPS_PER_AS = ( 28 / 4 )
MIN_HOPS_PER_AS = 7
It is interesting to note that more IP elements, without more meshing,
will create more hops. For example, a SONET network without significant
meshing will have more IP hops than a fully meshed IP/ATM network. There
are many many things of more significant importance than how many IP/L3
hops a network has, however. Certain ATM and MPLS networks create
logical meshes which decrease (IP L3) hop counts in certain
circumstances. Pros/Cons all the way around.
-alan
Thus spake Thomas Gainer (TGainer@e-xpedient.com)
on or about Mon, May 14, 2001 at 05:59:35PM -0400: